Reaktion von Phosphinboran, Phenylphosphinboran und Phosphoniumjodid mit Natriumtetrahydridoborat

Abstract

The reaction of phosphine borane and phosphonium iodide with NaBH4 yields H2P(BH3)2-Na+ (I), of phenylphosphine borane PhHP(BH3)2-Na+ (II) hydrogen being evolved in both reactions. Methylphosphine borane, phenylphosphine and the anions of I and II do not react with NaBH4 on account of the reduced acidity of the hydrogen atoms bound to phosphorus. Likewise hydrogen is evolved if (PhHP·BCl2)3 reacts with NaBH4. © 1970 Springer-Verlag.