Abstract
The hydride complex [Ru(IPr)2(CO)H][BArF4], 1, reacts with InMe3 with loss of CH4 to form [Ru(IPr)2(CO)(InMe)(Me)][BArF4], 4, featuring an unsupported Ru−In bond with unsaturated Ru and In centres. 4 reacts with H2 to give [Ru(IPr)2(CO)(η2-H2)(InMe)(H)][BArF4], 5, while CO induces formation of the indyl complex [Ru(IPr)2(CO)3(InMe2)][BArF4], 7. These observations highlight the ability of Me to shuttle between Ru and In centres and are supported by DFT calculations on the mechanism of formation of 4 and its reactions with H2 and CO. An analysis of Ru-In bonding in these species is also presented. Reaction of 1 with GaMe3 also involves CH4 loss but, in contrast to its In congener, sees IPr transfer from Ru to Ga to give a gallyl complex featuring an η6 interaction of one aryl substituent with Ru.
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Riddlestone, I. M., Rajabi, N. A., Macgregor, S. A., Mahon, M. F., & Whittlesey, M. K. (2018). Well-Defined Heterobimetallic Reactivity at Unsupported Ruthenium–Indium Bonds. Chemistry - A European Journal, 24(7), 1732–1738. https://doi.org/10.1002/chem.201705796
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