How to lose as little as possible

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Abstract

Suppose Alice has a coin with heads probability q and Bob has one with heads probability p > q. Now each of them will toss their coin n times, and Alice will win iff she gets more heads than Bob does. Evidently the game favors Bob, but for the given p; q, what is the choice of n that maximizes Alice's chances of winning? We show that there is an essentially unique value N(q, p) of n that maximizes the probability f(n) that the weak coin will win, and it satisfies ⌊1/2(p-q) - 1/2⌋ k ≤ N(q, p) ≤ ⌈max (1-p,q)/p-q⌉. The analysis uses the multivariate form of Zeilberger's algorithm to find an indicator function Jn(q, p) such that J > 0 iff n < N(q; p) followed by a close study of this function, which is a linear combination of two Legendre polynomials. An integration-based algorithm is given for computing N(q, p). Copyright © 2011 DMFA Slovenije.

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Addona, V., Wagon, S., & Wilf, H. (2011). How to lose as little as possible. Ars Mathematica Contemporanea, 4(1), 29–62. https://doi.org/10.26493/1855-3974.178.12b

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