The crystal structure of double metal oxide, Cu3TiO4, which contains cupric and cuprous ions, has been studied by means of the single crystal X-ray diffraction analysis. Cu3TiO4 is obtained by heating the powder mixture with mixing ratio of Cu2O: CuO: TiO2 = 1: 1: 1 in a platinum crucible at 1050°C in air. Since Cu3TiO4 is decomposed to CuO and TiO2 in the temperature range 600~900°C, the reaction product needs to be cooled rapidly. The crystal is hexagonal with space group P63/mmc. There is one formula unit in the unit cell of dimensions: a0 = 3.04 Å, c0 = 11.46 Å. In this structure, cupric and titanic ions are distributed randomly on the equivalent positions which surrounded octahedrally by six oxygen neighbours. Each cuprous ion has two oxygen neighbours disposed in a straight line. The proposed rational formula of this compound is Cu2+(Cu2+, Ti4+)042–. © 1974, The Chemical Society of Japan. All rights reserved.
CITATION STYLE
Hayashi, K., Mizutani, N., & Kato, M. (1974). Crystal Structure of Double Metal Oxide, Cu3TiO4. Nippon Kagaku Kaishi, 1974(1), 6–10. https://doi.org/10.1246/nikkashi.1974.6
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