It is known that graphs on n vertices with minimum degree at least 3 have spanning trees with at least n/4∈+∈2 leaves and that this can be improved to (n∈+∈4)/3 for cubic graphs without the diamond K 4∈-∈e as a subgraph. We generalize the second result by proving that every graph with minimum degree at least 3, without diamonds and certain subgraphs called blossoms, has a spanning tree with at least (n∈+∈4)/3 leaves. We show that it is necessary to exclude blossoms in order to obtain a bound of the form n/3∈+∈c. We use the new bound to obtain a simple FPT algorithm, which decides in O(m)∈+∈O*(6.75 k ) time whether a graph of size m has a spanning tree with at least k leaves. This improves the best known time complexity for Max-Leaves Spanning Tree. © 2008 Springer-Verlag Berlin Heidelberg.
CITATION STYLE
Bonsma, P., & Zickfeld, F. (2008). Spanning trees with many leaves in graphs without diamonds and blossoms. In Lecture Notes in Computer Science (including subseries Lecture Notes in Artificial Intelligence and Lecture Notes in Bioinformatics) (Vol. 4957 LNCS, pp. 531–543). https://doi.org/10.1007/978-3-540-78773-0_46
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