Hydrogenation of methyl laurate was conducted over a Cu/ZnO/Al 2O 3 catalyst, using methanol as the solvent and hydrogen source, to give lauryl alcohol. In this process, the solvent underwent partial decomposition in contact with the catalyst to generate hydrogen, which served as the hydrogenation agent. The effect of different factors on the reaction was examined, to optimize production of lauryl alcohol with high conversion efficiency and selectivity. Use of methanol as the solvent not only favored the reaction, but also suppressed a side reaction involving transesterification between methyl laurate and lauryl alcohol. Under optimal reaction conditions, 91.8 % conversion of methyl laurate and 88.8 % yield of lauryl alcohol could be achieved. © 2011 IUPAC.
CITATION STYLE
Liang, S., Liu, H., Liu, J., Wang, W., Jiang, T., Zhang, Z., & Han, B. (2012). Hydrogenation of methyl laurate to produce lauryl alcohol over Cu/ZnO/Al 2O 3 with methanol as the solvent and hydrogen source. Pure and Applied Chemistry, 84(3), 779–788. https://doi.org/10.1351/PAC-CON-11-06-09
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