Operators with diskcyclic vectors subspaces

10Citations
Citations of this article
1Readers
Mendeley users who have this article in their library.

This article is free to access.

Abstract

In this paper, we prove that if T is a diskcyclic operator then the closed unit disk multiplied by the union of the numerical range of all iterations of T is dense in (Formula presented.). Also, if T is a diskcyclic operator and |λ| ≤ 1, then T − λI has dense range. Moreover, we prove that if α > 1, then (Formula presented.) is hypercyclic in a separable Hilbert space (Formula presented.) if and only if (Formula presented.) is diskcyclic in (Formula presented.). We show at least in some cases a diskcyclic operator has an invariant, dense linear subspace or an infinite dimensional closed linear subspace, whose non-zero elements are diskcyclic vectors. However, we give some counterexamples to show that not always a diskcyclic operator has such a subspace.

Cite

CITATION STYLE

APA

Bamerni, N., & Kılıçman, A. (2015). Operators with diskcyclic vectors subspaces. Journal of Taibah University for Science, 9(3), 414–419. https://doi.org/10.1016/j.jtusci.2015.02.020

Register to see more suggestions

Mendeley helps you to discover research relevant for your work.

Already have an account?

Save time finding and organizing research with Mendeley

Sign up for free